47d500715a
Some versions of bottle.py don't deal well with the "if" inside the lambda, so work around it by just using comparison and simplifying the function. Signed-off-by: Alberto Bertogli <albertito@blitiri.com.ar>
57 lines
1.5 KiB
HTML
57 lines
1.5 KiB
HTML
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
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"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
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<html xmlns="http://www.w3.org/1999/xhtml">
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<head>
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% if not dirname.raw:
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% relroot = './'
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% else:
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% relroot = '../' * (len(dirname.split('/')) - 1)
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% end
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<title>git » {{repo.name}} »
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{{repo.branch}} » {{dirname.unicode}}</title>
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<link rel="stylesheet" type="text/css"
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href="{{relroot}}../../../../../static/git-arr.css"/>
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<meta http-equiv="content-type" content="text/html; charset=utf-8"/>
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</head>
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<body class="tree">
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<h1><a href="{{relroot}}../../../../../">git</a> »
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<a href="{{relroot}}../../../">{{repo.name}}</a> »
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<a href="{{relroot}}../">{{repo.branch}}</a> »
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<a href="{{relroot}}">tree</a>
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</h1>
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<h3>
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<a href="{{relroot}}">[{{repo.branch}}]</a> /
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% base = smstr(relroot)
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% for c in dirname.split('/'):
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% if not c.raw:
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% continue
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% end
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<a href="{{base.url}}{{c.url}}/">{{c.unicode}}</a> /
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% base += c + '/'
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% end
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</h3>
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<table class="nice ls">
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% key_func = lambda (t, n, s): (t != 'tree', n.raw)
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% for type, name, size in sorted(tree.ls(dirname.raw), key = key_func):
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<tr class="{{type}}">
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% if type == "blob":
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<td class="name"><a href="./f={{name.url}}.html">
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{{!name.html}}</a></td>
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<td class="size">{{size}}</td>
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% elif type == "tree":
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<td class="name">
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<a class="explicit" href="./{{name.url}}/">
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{{!name.html}}/</a></td>
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% end
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</tr>
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% end
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</table>
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</body>
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</html>
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