core/txpool/blobpool: calculate log1.125 faster (#29300)
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@ -23,8 +23,8 @@ import (
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"github.com/holiman/uint256"
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)
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// log2_1_125 is used in the eviction priority calculation.
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var log2_1_125 = math.Log2(1.125)
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// log1_125 is used in the eviction priority calculation.
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var log1_125 = math.Log(1.125)
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// evictionPriority calculates the eviction priority based on the algorithm
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// described in the BlobPool docs for both fee components.
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@ -57,8 +57,8 @@ func evictionPriority1D(basefeeJumps float64, txfeeJumps float64) int {
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// dynamicFeeJumps calculates the log1.125(fee), namely the number of fee jumps
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// needed to reach the requested one. We only use it when calculating the jumps
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// between 2 fees, so it doesn't matter from what exact number with returns.
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// it returns the result from (0, 1, 1.125).
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// between 2 fees, so it doesn't matter from what exact number it returns.
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// It returns the result from (0, 1, 1.125).
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//
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// This method is very expensive, taking about 75ns on a very recent laptop CPU,
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// but the result does not change with the lifetime of a transaction, so it can
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@ -67,7 +67,7 @@ func dynamicFeeJumps(fee *uint256.Int) float64 {
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if fee.IsZero() {
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return 0 // can't log2 zero, should never happen outside tests, but don't choke
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}
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return math.Log2(fee.Float64()) / log2_1_125
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return math.Log(fee.Float64()) / log1_125
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}
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// intLog2 is a helper to calculate the integral part of a log2 of an unsigned
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